if f(x)=1-x^2/3+16/x then find the value of f'(-8)
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f(-8)= 1- (-8)^2/3 + 16/-8
=(1-4) - 2
=1-4-2
=-5
ans is -5
=(1-4) - 2
=1-4-2
=-5
ans is -5
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