Question

If f(x) = √1-x² and g(x) = logx then find fog and gof​

Answer 1

It has given that, f(x) = √(1 - x²) and g(x) = logx

To find : we have to find the value of fog and gof.

solution : here f(x) = √(1 - x²) and g(x) = logx

fog = f(g(x))

= f(logx)

= √{1 - (logx)²}

Therefore the fog will be √{1 - (logx)²}

gof = g(f(x))

= g{√(1 - x²)}

= log√(1 - x²)

Therefore the gof will be log√(1 - x²)

also read similar questions :If f(x) =x² and g(x) = x+1.show that gof not equal to fog

https://brainly.in/question/17331391

Find gof and fog, if

$f(x)=8x^{3}\\g(x)= x^{\frac{1}{3} }$

https://brainly.in/question/17842835

Answer 2

Answer:

It has given that, f(x) = √(1 - x²) and g(x) = logx

To find : we have to find the value of fog and gof.

solution : here f(x) = √(1 - x²) and g(x) = logx

fog = f(g(x))

= f(logx)

= √{1 - (logx)²}

Therefore the fog will be √{1 - (logx)²}

gof = g(f(x))

= g{√(1 - x²)}

= log√(1 - x²)

Therefore the gof will be log√(1 - x²)

also read similar questions :If f(x) =x² and g(x) = x+1.show that gof not equal to fog

https://brainly.in/question/17331391

Find gof and fog, if

$$\begin{lgathered}f(x)=8x^{3}\\g(x)= x^{\frac{1}{3} }\end{lgathered}$$

https://brainly.in/question/17842835