Question

If f (x)=10x^2-13x+13
Then solve the equation f(x)=16

Answer 1

f(x) = 16
=>
10x²-13x +13 = 16

= 10x²-13x-3 =0
Now
d=b²-4ac { where b = coffecient of x
a = coffecient of x²
c = constant
d = 169 + 120
=> d = 289
roots are -b±√d/2a
=> x = 13±17/20