if f(x)= 10x³-5x²+8 then prove that dy/dx =30x²-10x
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Let, y = f(x) = 10x³ - 5x² + 8
So, differentiating both sides with respect to x, we get
dy/dx = d/dx (10x³ - 5x² + 8)
= 10 d/dx (x³) - 5 d/dx (x²) + d/dx (8)
= (10 × 3x²) - (5 × 2x) + 0
= 30x² - 10x
Hence, proved.
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