Question

if f(x) =16^x - log x with base 2 find f(1) and f(1/2)​

Answer 1

Answer:

f(1) = 16 and f(1/2) = 5

Step-by-step explanation:

$f(x) = 16^{x} - log_{2}(x)$

$1. \: \: x = 1$

$f(1) = 16^{1} - log_{2}(1)$

$= 16 - 0$

$f(1) = 16$

$2. \: \: x = \frac{1}{2}$

$f( \frac{1}{2} ) = {16}^{ \frac{1}{2} } - log_{2}( \frac{1}{2} )$

$= \sqrt{16} - log_{2}(2) ^{ - 1}$

$= 4 + log_{2}(2)$

$= 4 + 1$

$f( \frac{1}{2} ) = 5$

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