Question

if f(x) =16x-log2x,find f(1/4)
question of functions, answer please fast​

Answer 1

Answer:

f(x)=16^x + log2 ^x

Now,

f(1/4) = 16^(1/4) + log2 ^(1/4)

= (2^4) ^(1/4) +(- log2 ^4)

= 2 - log2^(2)^2

= 2 - 2 × 1

= 0

this is the correct answers

I hope it helps

Answer 2

Hope it helps :)

......;)