Question

If f(x^2- 1) = x^4- 7x^2+ k1 and
f(x^3 - 2) = x^6– 9x^3 +k2 then value of (k2– k1)
is
(1) 6
(2) 7
(3) 8
(4) 9

PLS ANSWER THIS QUESTION AS SOON AS POSSIBLE WITH EXPLANATION AND GIVE A RIGHT ONE....​

Answer 1

Answer:

8 is the answer

Step-by-step explanation:

Get

1) When we take x = 0 in , it becomes f(0-1)=f(-1)

f( – 1) = – 7 + k1 .....f(-1)=0-0+k1=k1..(a)

2) When we take x = 1 in , it becomes f(1-2)=f(-1)

f( – 2) = – 9 + k2 .....f(-1)=1-9+k2=k2-8...(b)

From (a) and (b), we get f(-1)=k1=k2-8.......k2-k1=8

Answer 2

Answer:

hey.. ek baat samajh mein nahi ayi.. ye question delete kaise hua...koi baat nahi ... dobara bana deta hun...

Step-by-step explanation:

$\huge{\boxed{\boxed{\bf{\red{Holla!!::}}}}}$.

just follow the attachment to get your answer...

$\mathfrak{\huge{\green{Lovely\: di\:!!!}}}$...