if f(x)=2 sinx ,g(x)=cox²x,then the value of (f+g)(π/3)
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Answer:
f(x) = 2sinx ...(i)
g(x) = cos²x ...(ii)
Adding (i) and (ii)
(f+g)(x) = 2sinx + cos²x
Putting x = pi/3
(f+g)(pi/3) = 2sin(pi/3) + cos²(pi/3)
= 2 × sqrt(3)/2 + (1/2)²
= 2sqrt(3)/2 + 1/4
=
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