if f x = 2 X raised to the power 4 - 2 x cube + 3 x square - a x minus b when divided by X - 1 the remainder is 6 then find the value of a + b
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By remainder theorem
Since fx when divided by x-1 is 6
X-1=0. => x=1
F(1) = 2*1^4-2*1^3+3*1^2-a*1-b =6
2-2+3-a-b =6
3-(a+b)=6
a+b = -(6-3)=-3
rishabh7:
it's by remainder theorem ... even my ans is coming -3 but in book it's written -4
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