if f(x) = 2^x, then range of the function is
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Answer:
let x=0,1,2,3,......
f(0)=2^0=1
f(1)=2^1=2
f(2)=2²=4
.
..
so x can range 0,1,2,3,4,.....
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Range of the function would be from open interval 0 to positive infinity.
Given
- f(x) = 2^x
To find
- range of the function
solution
we are given a function of 2 raised to x and are asked to find the range of the given function.
we know that a range of a function is the values that we obtain when the values of the domain are plugged in to the function .
The domain of the function is the real line
A an experimental mentality let us try to put some values to the function.
f(0) = 2^0 = 1
f(1) = 2^1 = 2
f(2) = 2^2 = 4
f(-1) = 2^(-1) = 1/2
From the above results we can reach a conclusion that the range of the function would be from open interval 0 to positive infinity.
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