Math, asked by surbhisharma161999, 10 months ago

if f(x) = 2^x, then range of the function is

Answers

Answered by himanshujol2677
2

Answer:

let x=0,1,2,3,......

f(0)=2^0=1

f(1)=2^1=2

f(2)=2²=4

.

..

so x can range 0,1,2,3,4,.....

Answered by Acharya01
0

Range of the function would be from open interval 0 to positive infinity.

Given

  • f(x) = 2^x

To find

  • range of the function

solution

we are given a function of 2 raised to x and are asked to find the range of the given function.

we know that a range of a function is the values that we obtain when the values of the domain are plugged in to the function .

The domain of the function is the real line

A an experimental mentality let us try to put some values to the function.

f(0) = 2^0 = 1

f(1) = 2^1 = 2

f(2) = 2^2 = 4

f(-1) = 2^(-1) = 1/2

From the above results we can reach a conclusion that the range of the function would be from open interval 0 to positive infinity.

#SPJ3

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