if f(x) = (2 x + x - 6)/log(3x - 5) find f(2)
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Answer:
f(x) = (2 x + x - 6)/log(3x - 5)
f(2) = (2x2 + 2 - 6)/log(3 x 2 - 5)
f(2) = (4 - 4) / log(6 - 5)
f(2) = 0/log 1
f(2) = 0
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