If f(x) = (2 - xcos x)/(2 + xcos x) and g(x) = logₑ x,(x > 0) then the value of the integral
π/⁴∫-π/₄ g(f(x))dx is:
(A) logₑ 1 (B) logₑ 2
(C) logₑ e (D)
logₑ 3
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given
f(x) = (2 - xcos x)/(2 + xcos x)
g(x) = logₑ x,(x > 0)
step by step explanation
refer to attachment
correct option is a) logₑ 1
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f(x) = (2 - xcos x)/(2 + xcos x)
g(x) = logₑ x,(x > 0)
refer to the attachment
correct option a)
Attachments:
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