Question

if f(X) =2x^2-5x +7 , find a polynomial whose zeroes are (2a +3b ) and (3a+2b).​

Answer 1

Answer:

This question is solved if given polynomial is 2x²-5x-7, other wise we are not getting real roots.

to get zeros of polynomial, we solve the given quadratic equation by factorisation

2x²-5x-7 = 0

2x²-7x+2x-7 = 0

x(2x-7)+(2x-7) = (2x-7)(x+1) = 0 ; hence zeros are -1 and 7/2

let a = -1 and b = 7/2 ; hence 2a+3b = 17/2 and 3a+2b = 4

hence required polynomial :- (x-4)(x-17/2) or (x-4)(2x-17) = 2x²-25x+68

Step-by-step explanation:

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Answer 2

Answer:

9

Step-by-step explanation:

is the answer pls mark me brainliest