if f(x)=2x^3-3x^2+12 then find f(2)
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f(x)=2x^3-3x^2+12
f(2) = 2(2^3) - 3(2^2) + 12
f(2) = 2(8) - 3(4) + 12
f(2) = 16 - 12 + 12
f(2) = 16
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