if f(x)=2x^3+mx^2-13x+n and 2 and 3 are roots of the equations f(x)=0, then values of m and n are- (a) 5,30 (b) -5,30 (c) -5,-30 (d) 5,-30
Answers
Answered by
62
Hello!
____________________________
To find 'm' and 'n' , we will put the values of zeroes of the equation in the place of 'x' and then equate the equation to zero.
=> 2 and 3 are the zeroes of the given equation f(x) = 2x^3 + mx² - 13x + n
CASE 1
f(2) = 2(2)^3 + m(2)² - 13(2) + n = 0
= 16 + 4m - 26 + n = 0
= 4m + n = 10 (equation 1)
CASE 2
f(3) = 2(3)^3 + m(3)² - 13(3) + n = 0
= 54 + 9m - 39 + n = 0
= 9m + n = -15 ( equation 2)
Using equation 1 and equation 2
=> 4m + n = 10
9m + n = -15
(-) (-) (+)
___________
-5m = 25
___________
m = 25/ -5
m = -5
Putting value of m in equation 1
=> 4m + n = 10
= 4(-5) + n = 10
= -20 + n = 10
= n = 30
Therefore, m = -5 and n = 30.
Therefore, the answer is (b) -5,30
I hope it helped.
Thank You!
____________________________
To find 'm' and 'n' , we will put the values of zeroes of the equation in the place of 'x' and then equate the equation to zero.
=> 2 and 3 are the zeroes of the given equation f(x) = 2x^3 + mx² - 13x + n
CASE 1
f(2) = 2(2)^3 + m(2)² - 13(2) + n = 0
= 16 + 4m - 26 + n = 0
= 4m + n = 10 (equation 1)
CASE 2
f(3) = 2(3)^3 + m(3)² - 13(3) + n = 0
= 54 + 9m - 39 + n = 0
= 9m + n = -15 ( equation 2)
Using equation 1 and equation 2
=> 4m + n = 10
9m + n = -15
(-) (-) (+)
___________
-5m = 25
___________
m = 25/ -5
m = -5
Putting value of m in equation 1
=> 4m + n = 10
= 4(-5) + n = 10
= -20 + n = 10
= n = 30
Therefore, m = -5 and n = 30.
Therefore, the answer is (b) -5,30
I hope it helped.
Thank You!
Anonymous:
m deleting my account.. bye-bye Anshu.. will miss u :))
Answered by
8
Answer:
see the attachment...
Attachments:
Similar questions
Math,
7 months ago
Social Sciences,
7 months ago
Math,
1 year ago
Math,
1 year ago
Geography,
1 year ago