if f (x)=2x^+3x+2/x^+1,then find f (1/x) is.
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Step-by-step explanation:
soln:
Given;
f(x)=2x^+3x+2/x^+1
f(1/x)=?
Now;
f(1/x)={2(1/x)^+3(1/x)+2}/{(1/x)^+1}
={(2/x^)+(3/x)+2}/}/{(1/x^)+1}
=[{ 2+3x+2x^}/x^]/[{1+x^}/x^] :(x^/x^=1)
=2x^+3x+2/x^+1
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