If f(x) = 2x^4-2x^3+3x^2-ax+b is a polynomial such that when it is divided
by (x-1) and (x+1) the remainders are respectively 7 and 19.
Determine the value of a and b.
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Answer:
a = 4 and b = 8
Step-by-step explanation:
Given that
f(x) = 2x⁴-2x³+3x²-ax+b
f(1) = 7 ----- (1)
f(-1) = 19 ------(2)
From (1):
f(1) = 2 - 2 + 3 - a + b = 7
=) - ( a - b ) = 4
a - b = -4 ----- (3)
From (2):
f(-1) = 2 + 2 + 3 + a + b = 19
=) a + b = 12 -------- (4)
From (3) and (4):
(3)
a - b = -4
-b = -4 - a
b = 4 + a
(4)
a + b = 12
a + a + 4 = 12
2a = 8
a = 4
(4)
a + b = 12
4 + b = 12
b = 8
hope it helps you..
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