If f(x)=2x^4-9x^3+5x^2+3x-1 and 2- root3,2+ root3. Find other two zeroes?
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X=2+√3 and x=2-√3 are zeros of p ( x )
( x -2 -√3) ( x-2 +√3)
(using identity ( a - b) ( a + b) = a^2 - b^2
then,
( x - 2)^2 - (√3)^2
x^2 + 4 - 4x - 3
x^2 + 1 - 4x
When we divide p ( x ) by ( i ) we get the other zeros
Other zeros are :- x = 1 and x = -1/2
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