Math, asked by pasa25, 4 months ago

If f(x)=2x-5 and g(x)=3x+1 are two functions then find gf^-1 (5).​

Answers

Answered by janu0098
5

Answer:

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Answered by hukam0685
0

Value of   \bf \: {gof}^{ - 1}(5) \: is \:   \frac{19}{6}  \\

Given:

  • If two functions are
  • f(x) = 2x - 5 and g(x) = 3x + 1 \\

To find:

  • Find the value of  {gof}^{ - 1} (5) \\

Solution:

Concept to be used:

  • Find gof.
  • Find inverse of gof.
  • put the value in inverse.

Step 1:

Find gof.

Put the value of f(x) in g(x).

gof(x)= 3(2x - 5) + 1 \\

or

gof(x)= 6x - 15 + 1 \\

or

\bf gof(x) = 6x - 14 \\

Step 2:

Find inverse of gof.

Let inverse of gof is y.

So,

y = 6x - 14 \\

or

x =  \frac{y + 14}{6}  \\

or

We can write

 \bf {gof}^{ - 1}(x) =  \frac{x + 14}{6}  \\

Step 3:

Put x= 5

 {gof}^{ - 1} (5) =  \frac{5 + 14}{6}  \\

or

 \bf {gof}^{ - 1} (5) =  \frac{19}{6}  \\

Thus,

Value of  {gof}^{ - 1} (5) \: is \:   \frac{19}{6}  \\

Learn more:

1) If f(x) = eˣ and g(x) =  log_{e} x , then show that fog = gof and find f⁻¹ and g⁻¹.

https://brainly.in/question/6960496

2) If f(x) = 2, g(x) = x², h(x) = 2x for all x ∈ R, then find (fo (goh) (x)).

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