If f(x)=2x-7/9 find f^-1(x)
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Answer:
E = kqx/(r² + x²)^3/2
here x is the distance
between centre of ring
to observation point on the axis of ring,
r is the radius of ring and q
is the charged particle.
Hence, at x = r/√2 ,
E will be maximum .
Step-by-step explanation:
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