Question

if f(x)=2x²+bx+c, f(0)=3, f(2)=1 , then find f(1)​

Answer 1

Answer:

0

Step-by-step explanation:

F(0) = 3

2(0)² + b(0) + c = 3

c= 3

F(2) = 1

2(2)² + b(2) +3 = 1

8+ 2b = -2

2b =-10

b= -5

F(1) = 2(1)² + -5(1) + 3

= 2-5+3

=0

Answer 2

Answer:

0

Step-by-step explanation:

Concept

• The polynomial equation whose highest degree is two is called a quadratic equation. The equation is given by ax² + bx + c = 0, where a ≠ 0.

Solution

$f(x)=2 x^{2}+b x+c_{r}$

$f(0)=3$

$\Rightarrow 3=c$

$\text { and } f(2)=1$

$\Rightarrow 1=8+2 b+c$

$\Rightarrow 2 b+3=-7$

$\Rightarrow b=-5$

$\therefore f(1)=2 \times 1^{2}+(-5) \times 1+3=2-5+3 =0$ .

#SPJ2