Question

If f(x) =2x³— 13x²+17x+12,then the value of f(x) at x=—½ is

Answer 1

Answer:

the value of f(x) at x=—½ is   0

Step-by-step explanation:

given that :

f(x) =2x³— 13x²+17x+12

we are to find the value of f(x) at x = - 1/2

so we need to substitute the value of f(x) by substituting the number (-1/2) in place of 'x'

⇒   f(x) =2x³— 13x²+17x+12  

⇒   f(x) = $2(-1/2)^3-13(-1/2)^2+17(-1/2)+12$

f(x) = $2(-1/8)-13(1/4)+17(-1/2)+12$

⇒ f(x) = $(-1/4)-13/4-17/2+12$

⇒  f(x) = $(-1-13)/4-17/2+12\\(-14)/4-17/2+12\\(-7)/2-17/2+12\\(-7-17)/2+12\\(-24)/2+12\\(-12)+12\\=0$

the value of f(x) at x=—½ is  0