If f(x + 3) = f(x + 1) + 4r + 12 4x and f(0) = 2, then what is f(400) ?
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Given, f(x+f(x))=4f(x) & f(1)=4
Substituting X=1 we get f(1+f(1))=4f(1)⇒f(1+4)=16⇒f(5)=16
Now substitute x=5, f(5+f(5))=4f(5)⇒f(5+16)=64=f(21)
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