if f(x+3) =f(x) +f(5)then prove that:f(2)=0 and f(5)=-f(-1)
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Answer:
Putting x=0,y=5 in the given equation, we get
f(0+5)=f(0)f(5)
⟹f(5)[f(0)−1]=0
⟹f(0)=1
Consider, f
′
(5)=
h→0
lim
h
f(5+h)−f(5)
=
h→0
lim
h
f(5)f(h)−f(5)
=
h→0
lim
h
f(5)[f(h)−1]
=f(5)
h→0
lim
h
f(h)−f(0)
=f(5)f
′
(0)=2×3=6
∴f
′
(5)=6
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