Question

if f (x)=3log6 (5x+1)then f (7)willbe

Answer 1

3 log6(35+1)=3log6*36
 =3 log 6³= 9log6

Answer 2

➡HERE IS YOUR ANSWER⬇

♧♧FORMULA♧♧

$log \: {a}^{m} = m \: loga \\ \\ log_{a} \: a = 1 \\ \\ log_{a} \: b = \frac{log \: b}{log \: a}$

♧♧SOLUTION♧♧


$f(x) = 3 log_{6}(5x + 1) \\ \\ so \: \: f(7) = 3 log_{6}(35 + 1) \\ \\ = 3 log_{6}(36) \\ \\ = 3 \: log_{6}( {6}^{2} ) \\ \\ = 3 \times 2 \times log_{6}(6) \\ \\ = 6 \times 1 \\ \\ = 6$

⬆HOPE THIS HELPS YOU⬅