If f(x)=3x^2+1 and g(x)=1-x, what is the value of (f-g)(2)
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Step-by-step explanation:
Here, f(x)= 3x²+1
g(x)= 1-x²
Put x=2 in both function f(x) and g(x), we get f(2)=13 and g(2)= -3
Now, (f-g)(2) = f(2)-g(2) =13-(-3)=13+3=16
Hint: f(2) = 3×2²+1 = 3×4+1= 13
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