If f'(x)=3x^2+4 and f(1)=7, find f(x).
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Step-by-step explanation:
f'(x) = 3x^2+4
f (1)= 7
Then
f(x)= x^3+4x+c and for x=1
Therefore 7=1+4+c
c= 2
Answer f(x) = x^3+4x+2
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