if f(x)=3x^2-5x+7show that f(-1)=3f(1)
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Answered by
1
f ( x ) = 3 x^2 - 5x + 7
f ( - 1) = 3 ( - 1 )^2 - 5( -1 ) + 7
= 3 + 5 + 7
= 15
f ( 1 ) = 3 ( 1 )^2 - 5 ( 1 ) + 7
= 3 - 5 + 7
= 5
5×3 = 15
so
f ( - 1 ) = 3 f ( 1 )
f ( - 1) = 3 ( - 1 )^2 - 5( -1 ) + 7
= 3 + 5 + 7
= 15
f ( 1 ) = 3 ( 1 )^2 - 5 ( 1 ) + 7
= 3 - 5 + 7
= 5
5×3 = 15
so
f ( - 1 ) = 3 f ( 1 )
Answered by
0
Heya!
f (x)=3x^2-5x+7
=) f (-1) = 3 (-1)^2 - 5 (-1) + 7
=3 (1) + 5 + 7
= 15
_ _ _ _ _ _ _ _ _ _ _ _
f (1) = 3 (1)^2 -5 (1) + 7
= 3 - 5 + 7
= 5
Then,
3 f (1) = 3×5
= 15
Hence, f (-1) = 3 f(1)
Hope it helps u.
f (x)=3x^2-5x+7
=) f (-1) = 3 (-1)^2 - 5 (-1) + 7
=3 (1) + 5 + 7
= 15
_ _ _ _ _ _ _ _ _ _ _ _
f (1) = 3 (1)^2 -5 (1) + 7
= 3 - 5 + 7
= 5
Then,
3 f (1) = 3×5
= 15
Hence, f (-1) = 3 f(1)
Hope it helps u.
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