Question

If f(x) = 3x + 2 + logx find f'(x)

Answer 1

f (x)=3x+2+log x
f' (x)=3+1/x

Answer 2

Given,
f ( x) = 3x + 2 + logx .

Now,
f'(x) = d/dx ( 3x + 2 + logx)

Using Sum Rule [ d/dx(u + v) = du/dx + dv/dx ]

f'(x) = d/dx(3x) + d/dx(2) + d/dx(logx)

= 3 dx/dx + 0 + 1/x

= 3 + 1/x

= 3x + 1 / x.

Formulae :

d/dx(x^n) = n x^n-1
d/dx ( Kx) = K d(x)/dx