if f(x) = 3x³ + kx - 8 and 2 is a zero of f (x) then the value of k is
Answers
Answered by
0
Answer:
2
Explanation
f(x)=f(x)=x
4
−x
3
−8x
2
+kx+12
If 3 is the zero of f(x),then,
f(3)=0
=3
4
−3
3
−8(3)
2
+k(3)+12
=81−27−72+3k+12
=93−99+3k
=>3k=6
=>k=2
Answered by
2
k = - 8
Step-by-step explanation:
Q.
If f(x) = 3x³ + kx - 8, and 2 is a zero of f(x), then value of k is,
Solution -
If
f(2) = 0 for f(x)
So,
f(2) = 3(2)³ + k(2) - 8 = 0
=> 3×2³ + 2k - 8 = 0
=> 3×8 + 2k - 8 = 0
=> 24 - 8 + 2k = 0
=> 16 + 2k = 0
=> 2k = - 16
=> k = -16/2
=> k = -8
So, the value of k is -8
hope it helps.
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