Question

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)? 6 – 3 – (4 + 3)2 6 – 3 – (4 – 32) 6(3) – 4 + 32 6(3) – 4 – 32

Answer 1

Given functions are $f(x)=4-x^2$ and g(x)=6x.

There are few answer choices given for (g-f)(3).

We have to evaluate (g-f)(3) to find which choice is correct.

(g-f)(3) means g(3)-f(3)

now to find values of g(3) and f(3) we will plug x=3 into given functions

$(g-f)(3)=g(3)-f(3) = 6(3)-[4-(3)^2]= 6(3)-4+3^2$

Hence final answer is $(g-f)(3) = 6(3)-4+3^2$