If f(x) = 4x 3 – 12x 2 + 14x - 3, find (i) f(2) (ii) f(-3) (iii) f(-1)
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hi I am not sure !! check itself
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vinayaksharma28:
part 1 is wrong rest all are correct and thanks for your support
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f(x) = 4x³ - 12x² + 14x - 3
(i)f(2)
=> f(2) = 4(2)³-12(2)²+14(2)-3
= 4(8)-12(4)+28-3
= 32-48+28-3
= 60-51
= 9
(ii)f(-3)
=> f(-3) = 4(-3)³-12(-3)²+14(-3)-3
= 4(-27)-12(9)-42-3
= -108-108-45
= -261
(iii)f(-1)
=> f(-1) = 4(-1)³-12(-1)²+14(-1)-3
= 4(-1)-12(1)-14-3
= -4-12-14-3
= -33
Hope it helps
(i)f(2)
=> f(2) = 4(2)³-12(2)²+14(2)-3
= 4(8)-12(4)+28-3
= 32-48+28-3
= 60-51
= 9
(ii)f(-3)
=> f(-3) = 4(-3)³-12(-3)²+14(-3)-3
= 4(-27)-12(9)-42-3
= -108-108-45
= -261
(iii)f(-1)
=> f(-1) = 4(-1)³-12(-1)²+14(-1)-3
= 4(-1)-12(1)-14-3
= -4-12-14-3
= -33
Hope it helps
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