Question

If f(x) = 4x4 – 2x3 – 3x2 – ax – b when divided by x – 1, the remainder is

6, then find the value of a – b.​

Answer 1

Step-by-step explanation:

x-1)4x^4 – 2x^3 – 3x^2 – ax – b (4x^3+2x^2-x

4x^4-4x^3

- +

__________

0 +2x^3-3x^2

2x^3-2x^2

- +

_____________

0-x^2-ax

-x^2+x

+ -

__________

0 -(a+1)x-b

remainder =6 (given)

-ax-x-b=6

ax+x+b= -6

let x=1

a+1+b=-6

a+b= -6-1 = -7

a+b= -7

let x= -1

-a-1-b= -6

-a-b= -6+1

-a-b = -5