If f(x)=6x^2+x-2 find the value of alpha /beta + beta /alpha
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hey mate :
given here
f(x)= 6x²+x-2
let ,here
alpha =a
beta =b
so,
a and b roots of given polynomial
now,
sum of roots = - coff.of x /coff. of x²
a+b. = -1/6
product of roots = constant part /coff.of x²
ab = -2/6
=-1/3
now,
a/b + b/a
= (a²+b²)/ab
=(a+b)²-2ab /ab
=[(-1/6)²-2× -1/3]/( -1/3)
=[1/36 + 2/3]/(-1/3)
=[(1+24)/36]/(-1/3(
=25/36 ×-3
= -25/12
i hopes its helps u
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