if f(x)=7^x^3+3x (x>0) then find f'(x)
Answers
Answered by
6
Answer:
f'(x) = 3(7x² + 1)
Step-by-step explanation:
f(x) = 7x³ + 3x
f'(x) = 3(7x²) + 3(1)
= 21x² + 3
= 3(7x² + 1)
Answered by
0
Answer:
u r ans is wrong
dude check it once again
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