Question

If f(x) = ax ^ 2 + bx + c and f(0) = - 3 , f(- 1) = 6, f(2) = 9 find the value of f(1)​

Answer 1

Answer:

question:-

If f(x) = ax ^ 2 + bx + c and f(0) = - 3 , f(- 1) = 6, f(2) = 9 find the value of f(1)

answer:-given f(x) = ax^2 + bx + c

(i) put x=1 , f(1) = a+b+cbut given that f(1) = 8 hence a+b+c = 8——————-(1)

(ii) put x=-1 , f(-1) = a-b+cbut given that f(-1) = 4 hence a-b+c = 4——————-(2)

consider (1) + (2) :- a+b+c + a-b+c = 8 + 42a + 2c = 122(a+c) =12a+c = 6.

hope it helps you!!

Answer 2

Answer

f(x) = ax2 +bx+c

f(1)=a*1+b*1+c=0

a+b+c=0....(1)

f(-1) =a(-1)²+b(-1)+c=5

a-b+c=5....(2)

add (1) and (2)

2a+2c=5

2(a+c)=5

a+c=5/2

solve your question like it ok

hope it will help u