Question

if f(x) =ax^2+bx+c then f'(x) =?​

Answer 1

Answer:

2ax+b

Step-by-step explanation:

f'(x) is nothing but derivative

so

d\dx(f(x))= f'(x) = d/dx(ax²+bx+c)

=d/dxax²+d/dxbx+d/dxc

=2ax+b(1)+0

c is constant so derivative of c is 0