Question

If f(x)=ax+b,then find the zero of f(x)

Answer 1

Answer:

So, if f(x) = ax+b, then f'(x) will be the first derivative of the function with respect to x.

f'(x) = d(ax+b)/dx

This actually means that we need to find the change in f(x) for every small change in x. Since a and b are constants, there will be no change in them with respect to x.

f'(x) = d(ax)/dx + d(b)/dx

Since ‘b' is a constant, d(b)/dx = 0 and in d(ax)/dx, we can take ‘a’ outside the derivative as a constant.

f'(x) = a d(x)/dx + 0

The derivative of x with respect to x is 1,i.e., d(x)/dx = 1.

So, f'(x) = a (1) + 0 = a

The final answer would be

If f(x) = ax+b, then f'(x) = a

Answer 2

Answer:

x=-b/a

Step-by-step explanation:

f(x)=ax+b

f(x)=0

ax+b=0

ax=-b

x=-b/a