If f(x) = (ax + b)", (x > -b/a),then find f'(x).
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Answer:
Given, f(x)=(ax+b)cosx+(cx+d)sinx
Thus f
′
(x)=(ax+b)(−sinx)+acosx+csinx+(cx+d)cosx
=(−ax−b+c)sinx+(a+cx+d)cosx
Also given, f
′
(x)=xcosx
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