If f(x) = ax+-bx~+x+5 and f(-3) = 2, then what is the
value of f(3)?
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F(3)= a.3.4+b.3.2+3+5= 12a+ 6b +8
now acc. to question
F(-3)= 2
a.(-3).4+b.(-3).2 -3 + 5=2 -12a-6b+2=2
-12a-6b=0
2a+b=0
b=-2a
substitution in very first equation
12a+ 6.(-2a) +8
12a-12a+8
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