If f(x) = ax - bx2 + x + 5 and f(-3) = 2, then f(3) =
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8 is your required answer
Answered by
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Answer:
f(3) = 3a- 6b+8
f( -3) = -3a + 6b +2
f(-3) = 2
therefore comparing
2= -3a +6b +2
0 = -3a +6b
therefore 3a-6b= 0............(1)
putting value of 1 in f(3)
we get
f(3) = 0+8
=8
I hope you got it
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