Question

If f(x)=ax^n,a is different from 0 &f(xy)=f(x)f(y),what is the value of a?​

Answer 1

Answer:

given that f(x)=a.x*n

and f(xy)=f(x)f(y)

so , according to the define of question f(xy)=a(xy)*n

f(xy)=a.(x*n)(y*n) & f(x)f(y)=a.(x*n).a.(y*n)

so if we take f(xy)=f(x)f(y)

a.(x*n)(y*n)=(a*2).(x*n).(y*n)

a=a*2

a*2-a=0

a (a-1)=0

and a is different from zero.so a=1.