Question

If f(x)=ax square -bx+6 and f(2)=3 and f(4)=30. find a and b​

Answer 1

Answer:

Step-by-step explanation:

f(2)=3

4a-2b+6=3

4a-2b+3=0(1)

f(4)=30

16a-4b=24(2)

After solve the both equation we get

a=15/4 &b=9

Answer 2

The value of a is $\frac{15}{4}$ and b is 9.

Step-by-step explanation:

Given : If $f(x)=ax^2-bx+6$ and f(2)=3 and f(4)=30.

To find : The value of a and b​ ?

Solution :

$f(x)=ax^2-bx+6$

Substitute x=2,

$f(2)=a(2)^2-b(2)+6$

$3=4a-2b+6$

$4a-2b=-3$  .....(1)

Substitute x=4,

$f(4)=a(4)^2-b(4)+6$

$30=16a-4b+6$

$16a-4b=24$

$4a-b=6$  .....(2)

Subtract (1) and (2),

$4a-b-(4a-2b)=6-(-3)$

$b=9$

Substitute in (1),

$4a-2(9)=-3$

$4a-18=-3$

$4a=-3+18$

$4a=15$

$a=\frac{15}{4}$

Therefore, the value of a is $\frac{15}{4}$ and b is 9.

#Learn more

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