If f(x)=ax²+bc+c has no real zeros and a+b+c<0, then
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The graph of the function satisfying the given conditions is shown in the above picture.
We can observe that the graph doesn't touch the X-axis i.e. it doesn't have any real roots and the value of f(1)=a+b+c<0.
Now substitue x=0.
Then we can observe that f(0)=c<0
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