Question

if f(x)=ax2+bx+c has no real zeroes and a+b+c<0,then find c????

Answer 1

If f(x) has no real roots then D<0,
Therefore, D=b²-4ac<0
⇒b²-4ac<0
⇒b²<4ac
⇒c>b²/4ac
∴, c=b²/4ac
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