Question

If f(x) = ax² + bx + c has no real zeros and a + b + c < 0, then
A. c = 0
B. c > 0
C. c < 0
D. None of these

Answer 1

Answer:

answer B is correct It think

Answer 2

Answer: C

$f(1)=a+b+c<0$

Here, having no roots means $f(x)\neq 0$. (On the x, y plane.)

$f(1)<0$ and $f(x)\neq 0$, therefore $f(x)<0$. --- 1

$f(0)<0$ From 1

$f(0)=c$ --- 2

Therefore, $c<0$.

Answer is C.

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