Question

If f(x) ={cos^2x+sin^4x/sin^2x+cos^4x
for x e R then f(2018)=​

Answer 1

Step-by-step explanation:

the answer will be xnot 5 sin lat into cos lat

f2018. is equal yo 19875

Answer 2

We have given that,

$f(x) = \frac{cos^2x+sin^4x}{sin^2x+cos^4x}$  for x e R then $f(2018)=$

lets find out,

lets use the following formula,

$sin^{2} x+cos^{2} x=1$

$f(x) = \frac{cos^2x+sin^4x}{sin^2x+cos^4x}$

$f(x) = \frac{1-sin^2x+sin^4x}{1-cos^2x+cos^4x}$

$f(x) = \frac{1-sin^2x+(1-sin^4x)}{1-cos^2x+(1-cos^4x)}$

$f(x) = \frac{1-sin^2xcos^2}{1-cos^2xsin^2x}=1$

$f(2018)=1$