If f(x) = cosec x + cot x, find .
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Answer:
-2 - √2
Step-by-step explanation:
Hi,
Given that f(x) = cosec x + cot x
We know that d/dx(cot x) = - cosec² x
and d/dx ( cot x) = -cosec x cot x
f(x) = cosec x + cot x
f'(x) = -cosec²x - cosec x.cot x
f'(π/4) = - cosec²(π/4) - cosec(π/4)cot(π/4)
= -2 - √2.
Hence, the value of f'(π/4) is -2 - √2.
Hope, it helps !
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