Question

If f(x)=e^x+2x-1,then find f(0),f(1/2)​

Answer 1

We have,

f(x) =

${e}^{x} + 2x - 1$

Putting x = 0, we get

$f(0) = {e}^{0} + 2 \times 0 - 1 \\ = > 1 + 0 - 1 \\ = > 0$

Putting x = 1/2, we get

$f( \frac{1}{2} ) = {e}^{ \frac{1}{2} } + 2 \times \frac{1}{2} - 1 \\ = > \sqrt{e} + 1 - 1 \\ = > \sqrt{e}$

Hence, f(0) = 0 and f(1/2) =

$\sqrt{e}$

Regards

Kshitij