Question

if f(x)=e^x+cos2x find f(0)​

Answer 1

Answer:

the answer to this question is 2

step-by-step explanation:

Given the equation is

$f(x) = {e}^{x} + cos2x$

we have to find f(x)=?

now we solve the given equation,

$f(x) = {e}^{x } + cos2x \\ = {e}^{x} + {cos}^{2}x - {sin}^{2} x \\ thefore \: f(0) = {e}^{0} + {cos}^{2} 0 - {sin}^{2} 0 \\ = 1 + 1 - 0 \\ = 2 \\ \\ \\ we \: know \: that \: cos2x = {cos}^{2} x - {sin}^{2} x \\ and \: cos0 = 1 \: and \: sin0 = 0$